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ddd [48]
4 years ago
12

jason wants to choose 9 players for his track team ,there are 12 players to choose from.how many different teams can jason make?

Mathematics
2 answers:
mote1985 [20]4 years ago
6 0
He could only make one team, considering that if you do 12-9, you are left with 3, and Jason wants to have his team consisted of 9 players. However, if you make 3 teams with 4 players on each team, or 4 teams with 3 players on each team, you could do that as well. 
PtichkaEL [24]4 years ago
3 0

Answer: 220 team can Jason make.

Step-by-step explanation:

Since, the total numbers of players = 12

The number of players in one team = 9,

Hence, the total combination of choosing 9 players out of 12 players

=^12C_9

=\frac{12!}{9!\times (12-9)!

=\frac{12\times 11\times 10\times 9!}{9!\times 3!}

=\frac{12\times 11\times 10}{3\times 2}

=\frac{1320}{6}=220

Thus, 220 team can Jason make.

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Katyanochek1 [597]

Answer:

(i)  64+192 x^2+240 x^4+160x^6

(ii) 1072

Step-by-step explanation:

<u>Part (i)</u>

Using Binomial series formula:

(2+x^2)^6=2^6+6C1 \cdot 2^{6-1}\cdot x^2+6C2 \cdot 2^{6-2}\cdot(x^2)^2+6C3 \cdot 2^{6-3}\cdot(x^2)^3

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              =64+192 x^2+240 x^4+160x^6

<u>Part (ii)</u>

<u />(1-\frac{3}{x^2})^2=(1-\frac{3}{x^2})(1-\frac{3}{x^2})

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(2+x^2)^6(1-\frac{3}{x^2})^2=(64+192 x^2+240 x^4+160x^6)\left(1-\dfrac{6}{x^2}+\dfrac{9}{x^4} \right)

=64-\dfrac{384}{x^2}+\dfrac{576}{x^4}+192x^2-1152+\dfrac{1728}{x^2}+240x^4-1440x^2+2160+...

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Therefore, the term independent of x = 64 - 1152 + 2160 = 1072

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Sloan [31]

Answer:

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Step-by-step explanation:

GCF is the greatest common factor of two numbers

Let us find the GCF of the given numbers 28 and 24

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∴ 28 + 24 = 4(7 + 6)

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