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ddd [48]
3 years ago
12

jason wants to choose 9 players for his track team ,there are 12 players to choose from.how many different teams can jason make?

Mathematics
2 answers:
mote1985 [20]3 years ago
6 0
He could only make one team, considering that if you do 12-9, you are left with 3, and Jason wants to have his team consisted of 9 players. However, if you make 3 teams with 4 players on each team, or 4 teams with 3 players on each team, you could do that as well. 
PtichkaEL [24]3 years ago
3 0

Answer: 220 team can Jason make.

Step-by-step explanation:

Since, the total numbers of players = 12

The number of players in one team = 9,

Hence, the total combination of choosing 9 players out of 12 players

=^12C_9

=\frac{12!}{9!\times (12-9)!

=\frac{12\times 11\times 10\times 9!}{9!\times 3!}

=\frac{12\times 11\times 10}{3\times 2}

=\frac{1320}{6}=220

Thus, 220 team can Jason make.

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Explanation

Step 1

because the ligth comes in the same angle, we have 2 similar triangles .

so,as the triangles are similar,the ratio of the shorter leg to the bigger leg must be equal.

\begin{gathered} ratio=\frac{shorter\text{ leg}}{\text{bigger leg}} \\ ratio1=ratio2 \\ \frac{h}{24}=\frac{4}{6} \end{gathered}

Step 2

solve for h

\begin{gathered} \frac{h}{24}=\frac{4}{6} \\ \text{cross multiply} \\ 6\cdot h=4\cdot24 \\ 6h=96 \\ \text{divide boths} \\ \frac{6h}{6}=\frac{96}{6} \\ h=16 \end{gathered}

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1 year ago
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Answer:

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0.2(10 -5c)= 5c -16

<em>Expand</em><em>:</em>

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<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

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