Question

Find the 66th term of the arithmetic sequence -10, 7, 24

Answer 1

Answer:

1095

Step-by-step explanation:

There is a common difference between consecutive terms , that is

7 - (- 10) = 24 - 7 = 17

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 10 and d = 17 , thus

$a_{66}$ = - 10 + (65 × 17) = - 10 + 1105 = 1095