All categories

3 years ago

Joe spent $4.36 for gasoline in driving 68 miles. How much would he spend in driving 85 miles?

Mathematics

2 answers:

Mariulka [41]3 years ago

5 0

($4.36/68miles)*85miles=$5.45

Wewaii [24]3 years ago

4 0

Answer:

$5.45

Step-by-step explanation:

68 miles -$4.36

85 miles -?

[85×4.36]68

5.45

You might be interested in

A line with a slope of 10 passes through the points ( -5, - 9) and ( - 4,a). What is the value of a?

Setler79 [48]

The slope is 10
(-5,-9)
(-4,-a)
a=-19
Because the slope is 10, that means when the input increases, the output will increases 10.

4 0

3 years ago

The graph for the equation y=-2x+1 is shown below. If another equation is graphed so that the system has no solution, which equa

12345 [234]

Y=-2x+3 (could be any y-int as long as it has the same slope)

This line is parallel to the original line so they never intersect

Therefore the answer is no solution

5 0

3 years ago

I need help with number 8 please. if you don't mind can you show your work so I know how to do it? Thanks in advance! :)

Trava [24]

You have to divide both sides by 5 because it states"5t" and you should get "t=20"

7 0

3 years ago

Jada was using square stickers that were 3/4in long to decorate the spine of a photo album. The spine is 10 and 1/2in long. If s

nevsk [136]

Answer:

Step-by-step explanation:

Given:

Square stickers that were 3/4 in long
The spine is 10 and 1/2 in long

If she laid the stickers side by side without gaps or overlaps so the number of sticker to cover the length of the spine:

$\frac{The length of the spine}{the length of the sticker}$

10 : $\frac{3}{4}$ ≈13

She needs 13 stickers cover the length of the spine

7 0

3 years ago

Read 2 more answers

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago