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Verizon [17]
3 years ago
11

Which method of traversing a tree would result in a sorted list for a binary search tree?

Computers and Technology
1 answer:
shutvik [7]3 years ago
6 0

Answer:

The inorder traversal make a binary search tree sorted.

Explanation:

The algorithm of inorder traversal is

1.  Traverse the left subtree.

2.  print the data .

3. Traverse the right subtree

In this algorithm left subtree  is visited first then it print the data or visit the data and finally it visited Right subtree .

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3 years ago
What is the limitation of computer<br>​
eimsori [14]

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3 years ago
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

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3 years ago
Which program will have the output shown below?
Ipatiy [6.2K]

Answer: >>> for count in range(10, 14):

   print(count)

Explanation:

just took the test on edg

4 0
3 years ago
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