Answer:
We know that C is the total number of cans in a complete case.
Victoria counts:
16 full cases, so in those we have: 16*C cans.
4 cases with 5 missing cans, so in those we have:
Then if each case has C cans, the cases that are missing 5 cans have:
C - 5 cans.
Then in those four cases we have a total of: 4*(C - 5) cans.
And Victoria knows that there are 220 cans, then we have that:
16*C + 4*(C - 5) = 220
16*C + 4*C - 20 = 220
16*C + 4*C = 220 + 20 = 240
20*C = 240
C = 240/20 = 12
Then each case has 12 cans.
Then the number of cans in the cases with missing cans is:
12 cans - 5 cans = 7 cans.
Step-by-step explanation:
Hope this helps!!!!!!!! :D
Answer:
0.0244 (2.44%)
Step-by-step explanation:
defining the event T= the chips passes the tests , then
P(T)= probability that the chip is not defective * probability that it passes the test given that is not defective + probability that the chip is defective * probability that it passes the test given that is defective = 0.80 * 1 + 0.20 * 0.10 = 0.82
for conditional probability we can use the theorem of Bayes. If we define the event D=the chip was defective , then
P(D/T)=P(D∩T)/P(T) = 0.20 * 0.10/0.82= 0.0244 (2.44%)
where
P(D∩T)=probability that the chip is defective and passes the test
P(D/T)=probability that the chip is defective given that it passes the test
Answer:
The answer to your question is: 20°
Step-by-step explanation:
Data
m∠XZY = 40
m∠XZB = 20
Process
1.- Find the measure of ∠ XAB
∠XAB = 40° because AB ║ YZ
2.- Find the measure of ∠ZAB
∠ZAB + ∠XAB = 180
∠ZAB = 180 - ∠XAB
∠ZAB = 180 - 40
∠ZAB = 140°
3.- Find the measure of ∠ABZ
The sum of the internal angles in a triangle equals 180°
∠AZB + ∠ZAB + ∠ABZ = 180
20° + 140° + ∠ABZ = 180
∠ABZ = 180 - 20 - 140
∠ABZ = 20°
Answer:
x=9
Step-by-step explanation:
Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.
Answer:
The z-distribution should be used for this problem.
Step-by-step explanation:
The population distribution is assumed to be normal. Which distribution to use?
If we have the standard deviation for the sample, we use the t-distribution.
If we use the standard deviation for the population, we use the z-distribution.
There is a known standard deviation of 2.2 minutes.
This means that 2.2 is the population standard deviation, and thus, the z-distribution should be used for this problem.
