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3 years ago

If the cos 90° = 0, then the sin 0° = _____. (1 point)

2 answers:

6 0

Sine and cosine are cofunctions in trigonometry. When you have two angles that are complements (and sum to 90 degrees), the sine of that angle is the cosine of its complement. (Look, for example, at a 30-60-90 triangle - - the sine of 30 degrees is the cosine of 60 degrees)

Or, as a formula, sin x° = cos (90 - x)° and cos x° = sin (90 - x)°.

We are told that the cosine of 90° is 0. Let's use our cofunction definiton.

cos (90°) = sin (90 - 90)° definition of cofunction

cos 90° = sin 0°

Since cos 90° = 0 then cos 90° = sin 0° = 0

Thus, sin(0°) = 0

Evgesh-ka [11]3 years ago

5 0

Sin 0 =0 that’s your answer

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When asked to write the domain for the equation y= |x - 6| + 3, Mary wrote the Domain is y < 3. What mistake(s) did Mary make

castortr0y [4]

Answer:

Ok, the domain is the set of values that we can input in a function.

In this case, we have:

y = Ix - 6I + 3.

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The correct domain is x, x ∈ R

Now, if we had (for example) something like:

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3 years ago

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

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