Answer:
D
Step-by-step explanation:
Since the line segment inside the triangle is parallel to the side of the triangle and intersects 2 sides then it divides those sides in proportion, that is
=
( cross- multiply )
45x = 3465 ( divide both sides by 45 )
x = 77 → D
Given that:
The triangle ABC and its image are shown below.
Step-by-step explanation:
In the below figure triangle A'B'C' is the image of triangle ABC.
We need to sketch a possible line that triangle ABC could translate along to create its image.
So, connect the corresponding vertices. So, the required lines are AA', BB' and CC '.
In translation, each point of the figure is shifted from point to another point in a particular distance and direction.
Point A, B and C are shifted to A' B' and C' respectively. So AA', BB' and CC' represents the distance and direction of translation.
From the figure it is clear that triangle ABC shifted 10 units right and 6 units down.
The quotient of that problem is 30
I think it is B. because the cost of the additional phone is $10. and $100 for each 2 Phones and $50 for the first one. the only way it makes sense is when you put the members...
The formula for the nth term of a geometric sequence:
![a_n=a_1 \times r^{n-1}](https://tex.z-dn.net/?f=a_n%3Da_1%20%5Ctimes%20r%5E%7Bn-1%7D)
a₁ - the first term, r - the common ratio
![54, a_2, a_3, 128 \\ \\ a_1=54 \\ a_4=128 \\ \\ a_n=a_1 \times r^{n-1} \\ a_4=a_1 \times r^3 \\ 128=54 \times r^3 \\ \frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\ \frac{64}{27}=r^3 \\ \sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\ \frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\ r=\frac{4}{3}](https://tex.z-dn.net/?f=54%2C%20a_2%2C%20a_3%2C%20128%20%5C%5C%20%5C%5C%0Aa_1%3D54%20%5C%5C%0Aa_4%3D128%20%5C%5C%20%5C%5C%0Aa_n%3Da_1%20%5Ctimes%20r%5E%7Bn-1%7D%20%5C%5C%0Aa_4%3Da_1%20%5Ctimes%20r%5E3%20%5C%5C%0A128%3D54%20%5Ctimes%20r%5E3%20%5C%5C%0A%5Cfrac%7B128%7D%7B54%7D%3Dr%5E3%20%5C%5C%20%5Cfrac%7B128%20%5Cdiv%202%7D%7B54%20%5Cdiv%202%7D%3Dr%5E3%20%5C%5C%0A%5Cfrac%7B64%7D%7B27%7D%3Dr%5E3%20%5C%5C%0A%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7B27%7D%7D%3D%5Csqrt%5B3%5D%7Br%5E3%7D%20%5C%5C%0A%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B%5Csqrt%5B3%5D%7B27%7D%7D%3Dr%20%5C%5C%0Ar%3D%5Cfrac%7B4%7D%7B3%7D)