Answer:
± 
, 
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are:
that correspond to the force of resistance on the mass by the action of the spring and
that is an external force with unknown direction (that does not specify in the enounce).
For determinate
we can use Hooke's Law given by the formula
where
correspond to the elastic constant of the spring and
correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

Now we apply Newton's 2nd Law and obtaint that...
±
= 




Finally...
± 
We know from the problem that there's not initial displacement and initial velocity, so...
and 
Finally the Initial Value Problem that models the situation describe by the problem is

Answer:
3:4
Step-by-step explanation:
x = 4 and x = - 9
In both cases the angles inside the parallel lines are same sided interior angles
24x - 1 + 20x + 5 = 180
44x + 4 = 180 (subtract 4 from both sides )
44x = 176 ( divide both sides by 44 )
x =
= 4
Similarly
x + 109 + x + 89 = 180
2x + 198 = 180 ( subtract 198 from both sides )
2x = - 18
x =
= - 9
Answer:
10/24 and 15/36, more answers possible
Step-by-step explanation:
if you multiply both the numerator and denominator by the same number, it will always be equivalent to 5/12, as you can simplify it back to that fraction.
5/12, multiply both by two, and you have 10/24
5/12, multiply both by three, and you have 15/36
Answer:
i
Step-by-step explanation: