Question

A local amusement park charges $21.50 per daily adult ticket and $14.75 per daily child's ticket. A group of 12 people paid $204.00 for tickets. Which system of equations could be used to find x, the number of adult tickets purchased, and y, the number of children's tickets purchased

Answer 1

Answer:

Step-by-step explanation:

Even though you didn't provide options from which to choose, you don't need them to figure out the system.  We need an equation that involves the NUMBER of people and then we need an equation that involves the MONEY earned.  Two different things here.

As for the number of people, we know that the number of adult tickets + the number of children = 12 people, so

x + y = 12.

That's the first equation.  Now for the money:

21.50x + 14.75y = 204.00

That's your system.

Answer 2

Step-by-step explanation and the Answer:

Let x= the number of adult tickets purchased and let y= the number of child tickets purchased. We know that 1) A local amusement park charges $21.50 per daily adult ticket and $14.75 per daily child's ticket. 2) A group of 12 people paid $204 for tickets. So $x+y=12$ is equation 1 and $21.50x+14.75y=204$ is equation 2. So therefore the answer is D. $x+y=12\\21.50x+14.75y=204$

OR

Even though you didn't provide options from which to choose, you don't need them to figure out the system.  We need an equation that involves the NUMBER of people and then we need an equation that involves the MONEY earned.  Two different things here. As for the number of people, we know that the number of adult tickets + the number of children = 12 people, so $x+y=12$ is the first equation. Now for the money 21.50x + 14.75y = 204 is the 2nd equation.  So therefore your system is D. $x+y=12\\21.50x+14.75y=204$