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alexgriva [62]
3 years ago
9

Drayton made this model to find the product of a 3 digit number and a 1 digit number

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
400x6=2400 This is how a find a product

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What is your number?
Goryan [66]

Answer:

13 and 11

Step-by-step explanation:

how is helpful

5 0
3 years ago
Read 2 more answers
R = 850 cm, s = 250 cm and t=940 cm. Find the measure of ZS tothe nearest 10th of a degree
faust18 [17]

To find the measure of the s angle que are going use the cosine law because we know all the sides of the triangule:

s² = r² + t² - 2*r*t * cos(S)

Then solve the equation

s² -r² - t² = -2*r*t * cos(S)

arccos ((s² -r² - t² /-2*r*t)) = S

arccos (((250)² -(850 cm)²-(940 cm)² /(-2* 850 cm*940 cm) = S

14.9 = S

round to the nearest 10th of a degree

15º = S

5 0
1 year ago
Does Anyone know the answer to this?
Amanda [17]

Exact form: x= NEGATIVE 6/7

8 0
3 years ago
The Washington, DC, region has one of the fastest-growing foreclosure rates in the nation, as 15,613 homes went into foreclosure
Ilia_Sergeevich [38]

Answer:

a) 0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b) 0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c) The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

Step-by-step explanation:

For each home, there are only two possible outcomes. Either it goes into foreclosure, or it does not. The probability of a home going into foreclosure is independent of other homes. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a. What is the probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure?

The foreclosure rate is 1.31% for the Washington, DC area, which means that p = 0.0131

We wanto to find, with n = 100:

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0131)^{0}.(0.9869)^{100} = 0.2675

P(X = 1) = C_{100,1}.(0.0131)^{1}.(0.9869)^{99} = 0.3551

P(X < 2) = P(X = 0) + P(X = 1) = 0.2675 + 0.3551 = 0.6226

0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b. What is the probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure?

Foreclosure rate of 0.87% for the nation, which means that p = 0.0087. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0087)^{0}.(0.9913)^{100} = 0.4174

P(X = 1) = C_{100,1}.(0.0087)^{1}.(0.9913)^{99} = 0.3663

P(X < 2) = P(X = 0) + P(X = 1) = 0.4174 + 0.3663 = 0.7837

0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c. Comment on the above findings.

The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

7 0
2 years ago
Evaluate : 9⁴xa⁷b⁴/ 3⁵xa⁴b⁴ ​
hjlf

Answer:

27a³

Step-by-step explanation:

9⁴xa⁷b⁴ / 3⁵xa⁴b⁴

(3²)⁴xa⁷b⁴ / 3⁵xa⁴b⁴

3⁸xa⁷b⁴ / 3⁵xa⁴b⁴

3³a³

27a³

7 0
3 years ago
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