What is the area of a rectangle with vertices with (2,3), (7,3), (7,10), and (2,10)

Mathematics

2 answers:

Harlamova29_29 [7]2 years ago

5 0

Answer:

35 square units

Step-by-step explanation:

multiply the base by the hight

Juli2301 [7.4K]2 years ago

3 0

Answer:

35 square units

Step-by-step explanation:

rectangle with vertices (2,3), (7,3), (7,10), and (2,10)

Area of a rectangle = length times width

Apply distance formula to find the distance between the sides

$D= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

points (2,3) and (7,3)

$D= \sqrt{(7-2)^2+(3-3)^2}=5$

points (7,3) and (7,10)

$D= \sqrt{(7-7)^2+(10-3)^2}=7$

Area of the rectangle = length times width = 5 times 7 = 35

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3 years ago

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Answer:

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