Answer:
B. (x-3,y+1)
Step-by-step explanation:
because they are integars
brainlyyest pls
I think it may be 5+3 and carry the one up top to get the sum of 56.
<span>5x ^2+ 15x = 0
</span><span>3x ^2 + 5x - 7 = 0
</span><span>x ^2 - 4x = 4x + 7</span>
![3^2+3[2^3( \sqrt{49}-2^2)(3^2-2^3)-2^2]](https://tex.z-dn.net/?f=3%5E2%2B3%5B2%5E3%28%20%5Csqrt%7B49%7D-2%5E2%29%283%5E2-2%5E3%29-2%5E2%5D%20)
Right off the bat, this may look crazy, but if we take it step by step, it will be much easier. So, let's take it step by step. If any step doesn't make sense to you, you can always hmu.
![9+3[8( 7-4)(9-8)-4]](https://tex.z-dn.net/?f=9%2B3%5B8%28%207-4%29%289-8%29-4%5D)
![9+3[8( 3)(1)-4] = 9+3[24-4] = 9+3[20]](https://tex.z-dn.net/?f=9%2B3%5B8%28%203%29%281%29-4%5D%20%3D%209%2B3%5B24-4%5D%20%3D%209%2B3%5B20%5D)

Your answer is
69.
-7x-3=25 (combine like terms)
-7x= 28 (add 3 on both sides)
x= -4 (divide -7 on both sides