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Schach [20]
3 years ago
11

X2+7x-8 please factor

Mathematics
1 answer:
vova2212 [387]3 years ago
8 0
x^2+7x-8=x^2+8x-x-8=x(x+8)-1(x+8)=(x+8)(x-1)
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What is : 65=4u+13 ????
Rus_ich [418]

Answer: 13


Step-by-step explanation:

65-13=54

54/4=13

Order of operations

6 0
3 years ago
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A bag contains 10 red marbles, 8 blue marbles and 2 yellow marbles. Find the theoretical probability of getting a yellow marble.
Rzqust [24]
(number of yellow marbles) / (overall number of marbles)
=
2/20
7 0
2 years ago
Y = x + 3<br>2y = 2x + 6​
Marina CMI [18]

Answer:

x=0

y=3

Step-by-step explanation:

2(x+3)=2x+6, substituting the first equation in the second

2x+6=2x+6, rearranging the equations

2x-2x=6-6

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6 0
3 years ago
Please help meeeeeee!
marishachu [46]

Answer:

2x^2+x-1/x^2-1

x^2+11x+18/x^2-11x+18

2x^2-5x+3/x^2+4x+3

Step-by-step explanation:

1.2 and 5

6 0
3 years ago
Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and
Jlenok [28]
We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

\frac{y}{x} = \frac{1}{8}  \\  \\ \Rightarrow x=8y \\  \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\  \\ \Rightarrow v=0

For the line with points (0, 0) and (1, 8), the equation is given by:

\frac{y}{x} = \frac{8}{1}  \\  \\ \Rightarrow y=8x \\  \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\  \\ \Rightarrow u=0

For the line with points (8, 1) and (1, 8), the equation is given by:

\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\  \\ \Rightarrow y-1=-x+8 \\  \\ \Rightarrow y=-x+9 \\  \\ \Rightarrow u+8v=-8u-v+9 \\  \\ \Rightarrow u=1-v

The Jacobian determinant is given by

\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\  \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\  \\ =63(-9)=|-576|=576
6 0
3 years ago
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