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romanna [79]
3 years ago
6

Calle had five times as many stickers as sara did and twice as many as juniper. Juniper had 25 stickers. How many stickers did t

hey have altogether?
Mathematics
1 answer:
n200080 [17]3 years ago
3 0

Calle: has twice as many as Juniper so = 2*25 = 50

she also has 5 times as many as sara so if she has 50, you divide 50/5 = 10

Calle has 50 stickers, Sara has 10 and Juniper has 25.

So all together they have 85 stickers.

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the weight of 3 kittins at one week of age were 3.6 ounces 4.2ounces and 3.3 ounces if each kitten has gained 2.3ounces how much
Leona [35]

Answer:

3.6 + 2.3 = 5.9

4.2 + 2.3 = 6.5

3.3 + 2.3 = 5.6

Step-by-step explanation:

4 0
2 years ago
What is the slope of the line graphed on the coordinate plane?​
Alekssandra [29.7K]

Answer:

-1/12

Step-by-step explanation:

slope=(-2-(-1))/(6-(-6))

-1/12

6 0
2 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
Can someone pleaseeeeeehelp me
Effectus [21]
the answer will be bbcuz
7 0
3 years ago
Suppose your car averages 38 miles per gallon on the high-
Stella [2.4K]

Answer:

a. around 36.36 hours; around 28.57 hours

b. $134.21; $159.38

Step-by-step explanation:

4 0
3 years ago
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