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Mila [183]
3 years ago
15

Which answer best describes the complex zeros of the polynomial function? f(x)=x3+x2−8x−8

Mathematics
2 answers:
lidiya [134]3 years ago
5 0

Answer:

a

Step-by-step explanation:

took the test

Valentin [98]3 years ago
4 0

we are given

f(x)=x^3+x^2-8x-8

We can use Descarte's sign rule to find number of real roots

Positive real roots:

f(x)=x^3+x^2-8x-8

we can see that number of sign changes in this function is 1

so, number of positive real root =1

Negative real roots:

Firstly, we will find f(-x)

f(-x)=(-x)^3+(-x)^2-8(-x)-8

f(-x)=-x^3+x^2+8x-8

we can see that number of sign changes in this function is 2

so, number of negative  real root =2

so, total number of real roots = number of positive real roots + number of negative real roots

total number of real roots =1+2

total number of real roots =3

Since, the degree of this polynomial is 3

so, maximum number of roots must be 3

We know that all roots are also called x-intercept because it crosses x-axis at that value

so, function will cross x-axis thrice

so, option-A.......Answer


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Answer:

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