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3 years ago

© 5 t-shirts and a hat costs £62.00

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

h = 7

t = 11

Step-by-step explanation:

5t + h = 62

2t + h = 29

h+5t = 62

h+2t = 29

h = 7

t = 11

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164 is 55% of what number? Please somebody help me

monitta

This is how you solve it; but first of all convert the percent into a decimal;55%= 0.55

0.55x = 164 (divide by 0.55 on both sides)
x = 164/0.55
x = 298.18 (rounded to the nearest hundredth)
so 164 is 55% of 298.18(rounded)

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3 years ago

1 What is the slope of the line through (-9,-6) and (3,-9)?

Setler [38]

Answer:

-2/3

Step-by-step explanation:

So the slope of the line that goes through the points and is m=3/2

Now flip the fraction and change the sign to get the answer -2/3

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3 years ago

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A plot of land has an area of 33.75 square feet. Jackson wants to put a 4-foot by 4-foot shed on the land. He can only do this i

Semenov [28]

The area of a trapezoid is
A = (1/2) h (b1 + b2)
where
h is the height
b1 is length of base 1
b2 is the length of base 2

We are given with the area and assuming that the trapezoid is isosceles, the length of base 1 is
b1 = 4 ft
If the height of the trapezoid is 4.5 feet, it ensures that the shed will fit inside the trapezoid patch of land. Therefore, the height of the trapezoid is 4.5 feet.

4 0

3 years ago

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170 percent converted to a fraction equals: ...?

Verdich [7]

There are several ways to do this by converting the percentage to a fraction by placing thee expression over 100100. Percentage means out of 100 and it will look like this 170/100.
Reduced the expression. 17/10
or in whole number it is 1 17/10

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3 years ago

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Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

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3 years ago