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3 years ago

Really confusing......

Mathematics

2 answers:

scZoUnD [109]3 years ago

7 0

Answer: $40.70

Step-by-step explanation:

60 x $0.37 = $22.20

170 x $0.37 = $62.90

62.90

- 22.20

$40.70

She spent $40.70 more.

valina [46]3 years ago

4 0

Answer:

She spent 40 more dollars or to be exact 40.70 dollars more then aiden

Step-by-step explanation:

Aiden bought 60 candles.

0.37*60 is equal to $22.20

Aidens sister bought 170 candles at same price of $0.37

0.37*170=$62.90

Now subtract

$62.90-22.20=$40.70

She spent 40 more dollars or to be exact 40.70 dollars more then aiden

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First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

1 year ago

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Alex73 [517]

$3, $1, $5, $2, $3, $9, $1 = $24 - $1 = $23 - $1 = $22.

$22 is the estimation of the bill when all of the amounts are rounded to the nearest dollar. The estimation is greater than the total bill which is 23 cents less than the estimation. The total on the register is reasonable and accurate.

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3 years ago

The lowest temperature ever recorded at Oymyakon in Russia was 96.2°F below 0°F. The lowest temperature ever recorded at Prospec

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Thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

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It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F

So the thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska was 80°F below 0° F

So the thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

7 0

3 years ago

Really confusing......​

Really confusing......