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xxMikexx [17]
3 years ago
14

A person is purchasing a new golf club bag. The compartment for the golf balls is approximately the shape of a rectangular prism

with the dimensions of 8 inches by 11 inches by 5 inches. Assuming golf balls are spherical with a 1.68 inch diameter, how many golf balls should fit in the compartment bag?
Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

The answer to your question is: 161 balls

Step-by-step explanation:

Data

rectangular prism = 8 in x 11 in x 5 in

diameter golf balls = 1.68 in     radius = 1.68/ 2 = 0.84 in

Formula

Volume rectangular prism = l x w x h

Volume sphere = (4/3)π r³

Process

Volume rectangular prism = 8 x 11 x 5 = 400 in³

Volume balls = (4/3) (3.1416) (0.84)³ = 2.48

# of balls in the compartment = volumen rectangular prism / volume balls

# of balls in the compartment = 400 / 2.48 = 161. 29

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<span>LCD(<span>115</span>, <span>95</span>, <span>38</span>) = LCM(15, 5, 8) = 23×3×5 = 120</span>
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The admission fee at a small to the school play is $1.50 for children (x) and $4.00 for adults (y). On opening night, the revenu
Alecsey [184]

Answer:

1.50x + 4.00y =5,050

Step-by-step explanation:


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3 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
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Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

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With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
Please help me! It’s due soon
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Answer:

<1= 135 degrees

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Step-by-step explanation:

This is because angle two and 6 are corresponding angles. you would then subtract 180 from 45 because angle 6 and 4 are consecutive angles. This would give you 135 degrees. Then angle 1 and angle 4 are verticla agles, making them equal to each other.

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