Answer:
Step-by-step explanation:
Given that
f(-2) = 1 and f(2) = 1
The question is here we have values for -1 and 1 the same and hence we must get a c such that f(c) =0
Because we are not getting here c value does it violate the intermedate value theorem
Please go through the conditions for intermediate theorem to be valid
If f(x) is continuous in the interval [a,b] and f is differentiable in the interval (a,b) and if f(b) = f(a) then we have a c in the interval (a,b) such that f(c) = 0
But our f(x) is not differntiable in the interval (-2,2) because at x =0 we get left derivative =-1 and right derivative =1
So f is not differntiable in the interval.
Hence intermediate theorem cannot be applied here.
Answer:
Step-by-step explanation:
Let x represent nickel
Then dimes be 2x and 2x-9
Quarter is 0.25
Total in the bag
x+2x+2x-9+0.25=3.75
Solve for x
5x=3.75+9-0.25
5x=12.5
x=2.5
Answer:
30 houses
Step-by-step explanation:
Time from 6:30 pm to 8:45 pm = 2 hr 15 min
Time in minutes = (2 hr × 60 min/hr) + 15 min = 135 min
Average visit = 9 min per 2 houses = 4.5 min per house
Number of visits = 135 min ÷ 4.5 min/house = 30 houses
Answer:
b
Step-by-step explanation:
when angle RST approach 180°, RT approach 65
when angke RST approach 0° , RT approach 5
Answer: Interest
Step-by-step explanation: