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miv72 [106K]
4 years ago
15

Suppose that an experiment is repeated four times. A certain event has probability 1/10 in a single repetition of the experiment

.
What is the probability that the event occurs every time in the 4 trials?
What is the probability that it never occurs?
What is the probability that it occurs at least once?
What is the probability that it occurs in the fourth trial only?
Mathematics
2 answers:
Mazyrski [523]4 years ago
8 0
Best thing you can do in order to answer all of this is to use the <span>Bernoulli trials. You can look for it and see if the answers I'm giving you are correct:
</span><span>Probability of occurring 4 times = (1/10)^4
Probability of never occurring = (9/10)^4
Probability that it occurs at least once = 1 - (9/10)^4
Probability that it occurs in the fourth trial only = (9/10)^3 * 1/10
</span>I think this is going to be very helpful
Basile [38]4 years ago
3 0

Answers:

1/10,000

6561/10,000

3439/10,000

729/10,000

Step-by-step explanation:

Plug in (1/10)^4

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2 years ago
What is 5/11 in decimal form? (round your answer to the nearest hundredth.)?
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3 years ago
-6x + 18 = 7- (4x + 9) help will give brainlyist
andreyandreev [35.5K]

Answer:

X = -5

Step-by-step explanation:

-6x + 18 = 7 - (4x + 9)

first we simplify the parentheses.

distribute the invisible number one created by the negative sign in front of the parentheses to get -6x + 18 = 7 - 4x - 9

then simplify further by subtracting 9 from the right side, leaving you with

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next, add 2 to both sides to isolate the variable.

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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