Question

Serious answers only. Do not answer if you dont know please!How does the graph of the circle described by x^2 + (y-7)^2 = 49 change when its equation is changed to (x +5)^2 + (y-4)^2 =64. Select each correct answer. The circles radious increases, The circle moves up, The circle moves left, The circles radious decreases, The circle moves down, The circle movea right.

Answer 1

Answer:

• The circles radious increases

• The circles moves left

• The circles moves down

Step-by-step explanation:

• The equation of a circle can be written as $(x-a)^2+(y-b)^2=r^2$, where "r" is the radious, and (a,b) are the coordenates in the axis x and b respectively.
• Then, in the first circle the coordenates are (0,7), which means that the circle will be center there, and the radious is 7 ($\sqrt{49}$).
• The second circle have different coordenates: (-5,4), which means that the circle has moved left (from 0  to -7 in the x axis) and down (from 7 to 4 in the y axis). Additionally, its radious has increased from 7 ($\sqrt{49}$, from 8 ($\sqrt{64}$).
• See the attached figure please.
• Then, the correct answers are:

1. The circles radious increases (from r=7 to r=8)
2. The circles moves left (from x=0 to x=-5)
3. The circles moves down (from y=7 to y=4)