The value of z score for the history class test of Opal’s test score is negative one (-1).
<h3>What is normally distributed data?</h3>
Normally distributed data is the distribution of probability which is symmetric about the mean.
The mean of the data is the average value of the given data. The standard deviation of the data is the half of the difference of the highest value and mean of the data set.
The z score for the normal distributed data can be given as,

The mean value of the scores of history class is,

The standard deviation value of the scores of history class is,

Here, the test score of the Opal’s is 72. Thus the z score for her test score can be given as,

Hence, the value of z score for the history class test of Opal’s test score is negative one (-1).
Learn more about the normally distributed data here;
brainly.com/question/6587992
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
4(x-2/3) = -18
4x - 8/3 = -18
4x = -54/3 + 8/3
4x = -46/3
x = -46/3 * 1/4
x = -46/12
x = -23/2
2x = -23/2 * 2
2x = -46/2
2x = -23
Answer:
<h3>The answer is 243.</h3>
Step-by-step explanation:
To evaluate the expression substitute the values of a , b , c and d into the above expression
a = - 9
b = - 7
c = 9
d = 3
So we have
2cd + 3ab = 2(9)(3) + 3(-9)(-7)
= 2(27) + 3( 63)
= 54 + 189
We have the final answer as
<h3>243</h3>
Hope this helps you