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iVinArrow [24]
3 years ago
11

When should you use graphing to solve a system?

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0
When you have order pairs Ex. (x,y) that would need to be plotted on a graph.
nignag [31]3 years ago
4 0
Yes you should. When using a system
You might be interested in
4/50 converted into a percentage
Arlecino [84]

Answer:

Step-by-step explanation:

\frac{4}{50}*100=4*2

            = 8%

3 0
3 years ago
Jamar and Peggy live on opposite sides of a park. Peggy counted how many steps it takes her to get from her house to Jamar's hou
creativ13 [48]

Answer:

A.96.25 steps.  B. Approximately 37 steps shorter

Step-by-step explanation:

From Pythagoras theory,

Hyp² = Adj² + Opp²

Hyp² = 52² + 81²

Hyp² = 2704 + 6561

Hyp² = 9265

Hyp = √9265

Hyp = 96.25 steps

= 81 + 52 = 133 - 96.25

= 36.75 or approximately 37 steps shorter

7 0
3 years ago
In the data set below, what is the mean absolute deviation?4461526If the answer is a decimal, round it to the nearest tenth.mean
bixtya [17]
I assume that the numbers are: 4,4,6,1,5,2,6
If so, then the MAD is 1.43

To find the MAD, you first find the mean of the list. It is 4.
Then find the absolute difference of each number from the mean.

Those values are: 0,0,2,3,1,2,2
Now find the mean of those numbers and you have about: 1.43
5 0
3 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
4 years ago
I need help with this please !!!
n200080 [17]

Answer: It's Congruent but not similar because the shape on top doesn't look like the bottom left.

Step-by-step explanation:

5 0
3 years ago
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