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3 years ago

Which of the following could be used to calculate the area of the sector in the circle shown?

Mathematics

2 answers:

mr Goodwill [35]3 years ago

8 0

Hello there.

Which of the following could be used to calculate the area of the sector in the circle shown?

π(10in)^2 37 over 360

schepotkina [342]3 years ago

3 0

The area of the sector in the circle can be calculated using the formula:
A = π r² θ / 360
where r is the radius and θ is the area subtended by sector. So,
A = π (10)² (37/360)

The answer is the first option.

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Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all

Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

$38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\$ $54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79$

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = $\frac{55+59}{2} = \frac{114}{2}=57$

In point b:

First-quarter $Q_1 = \frac{1}{4} \text{number of 8th call}$

$=\frac{1}{4} \times 30 th \\\\= 7.5 th$

The first quarterlies are $7.5th \ \ that \ is = (7+0.5)th\ \ term$

therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

$=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times 30 th \\\\=22.5 \ th = (22+0.5)th \ \ term$

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

$= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5$

In point c:

First decile $D_1 = \frac{1}{18} \text{number of 8th call}$

$= \frac{1}{10} \times 30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times 8\ th\ call\\\\=\frac{9}{10} \times 30 th \\\\=27th \ \ term\\\\\to D9 = 67$

In point d:

quartiles are:

$Q_1= 51.25 \\\\Q_3=66$

The right answers for the decile are:

$D_1=45.3 \\\\ D_9=76.4$

As for $D) P_{33} = 53.53$ will be available.

7 0

2 years ago

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SVETLANKA909090 [29]

Answer:

18.85 units 3

Step-by-step explanation:

7 0

2 years ago

The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadr

mamaluj [8]

In this case you divide 170 by 7 which = 24.29 so 24.29 is your answer, good luck.

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2 years ago

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Anastaziya [24]

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3 years ago

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likoan [24]

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4 0

3 years ago

Read 2 more answers