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Paladinen [302]
3 years ago
10

Assuming that the current interest rate is 6 percent, compute the present value of a five-year, 5 percent coupon bond with a fac

e value of $1,000. What happens when the interest rate goes to 7 percent? What happens when the interest rate goes to 5 percent?
Business
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

PV when interest rate is 6% = $957.88

PV when interest rate is 7%= $918

PV when interest rate is 5%= $1,000

Explanation:

The price of a bond is equivalent to the present value of all the cash flows that are likely to accrue to an investor once the bond is bought. These cash-flows are the periodic coupon payments that are to be paid annually and the par value of the bond that will be paid at the end of 5 years.  

During the 5 years, there are 5 equal periodic coupon payments that will be made. Given a par value equal to $1,000, in each  year, and a coupon rate equal to 5% the annual coupon paid will be = $50. This stream of cash-flows is an ordinary annuity.

The  PV of the cash-flows = PV of the coupon payments + PV of the par value of the bond

Assuming the current interest rate is 6 percent

PV =50*PV Annuity Factor for 5 periods at 6%+ $1,000* PV Interest factor with i=6% and n =5

= 50*\frac{[1-(1+0.06)^-^5]}{0.06}+ \frac{1,000}{(1+0.06)^5} = $957.88

The bond sells at a discount.

Assuming the current interest rate is 7 percent

PV =50*PV Annuity Factor for 5 periods at 7%+ $1,000* PV Interest factor with i=7% and n =5

= 50*\frac{[1-(1+0.07)^-^5]}{0.07}+ \frac{1,000}{(1+0.07)^5} = $918

The bond sells at a discount.

Assuming the current interest rate is 5 percent

PV =50*PV Annuity Factor for 5 periods at 5%+ $1,000* PV Interest factor with i=5% and n =5

= 50*\frac{[1-(1+0.05)^-^5]}{0.05}+ \frac{1,000}{(1+0.05)^5} = $1,000

The bond sells at par

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Sapphire Aerospace operates 52 weeks per year, and its cost of goods sold last year was $6,500,000. The firm carries eight items
OLEGan [10]

a. The average aggregate inventory value is <em>$336,000.</em>

b. The number of weeks of supply that the firm has is <em>3 weeks</em>, approximately (2.69 ($336,000/$6,500,000 x 52).

c. The inventory turnover of Sapphire Aerospace for last year was<em> 19.3x.</em>

<u>Question Completion</u>:

Category        Part Number        Average           Value        Total      Category

                                              Inventory Units    per Unit      Value        Totals

Raw Materials      RM-1                20,000               $1        $20,000

Materials             RM-2                 5,000                 5          25,000

                            RM-3                 3,000                 6           18,000

                            RM-4                  1,000                 8            8,000      $71,000

Work-in-process WIP-1                 6,000                10         60,000

                            WIP-2               8,000                 12         96,000   $156,000

Finished goods   FG-1                  1,000                65         65,000

                            FG-2                   500                88         44,000   $109,000

Total value of inventory                                               $336,000  $336,000

Inventory turnover = Cost of goods sold/Average inventory

= 19.3x ($6,500,000/$336,000)

Thus, the average inventory value is $336,000, while the inventory turnover was 19.3x.

Learn more about inventory turnover here: brainly.com/question/5701250

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Whether people use automatic or controlled processing for reacting to a persuasive message is often a function of ________.
kogti [31]
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Employees who are paid to complete a task, such as build a house, are paid on a(n) _____ basis
Ghella [55]

I'm pretty sure it hourly

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Direct labor or machine hours may not be the appropriate cost driver for overhead in all areas of manufacturing due to the compl
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Answer:

WATERWAYS CORPORATION

a.

Activity Cost                        Overhead          Actual Cost  

Pools Activity-                       Rates                Assigned

Based  

Irrigation installation                $  154.20    $1,995,502.20

Machining (all machine use)        $0.05      1,670,450.00

Customer orders                        $12                30,240.00

Design                                         $102.50              717.50

Selling                                         $16             353,600.00

b. Classification of activities by level:

Activities                                                                  Levels

Testing of products (if all items are tested)            Unit

Testing of products (if all items are not tested)    Batch  

Designing new products                                        Product  

Packaging                                                                Unit  

Molding                                                                    Product  

Assembling                                                              Batch  

Depreciation                                                            Facility  

Machine maintenance                                            Unit  

Advertising                                                              Product  

Equipment setups                                                  Batch  

Electricity required to run equipment                   Facility  

Requisitioning materials                                        Unit

Explanation:

a) Data and Calculations:

WATERWAYS CORPORATION

Activity Cost                                       Estimated   Expected       Actual Use

Pools                            Cost Drivers  Overhead  Use of Cost     of Drivers

                                                                              Drivers per

                                                                                Activity    

Irrigation installation Labor cost      $1,998,432   12,960                   12,941

Machining                 Machine hours 1,670,400   33,408,000  33,409,000

Customer orders      No. of orders        30,636     2,553                   2,520

Design                      Cost per design         820             8                      7

Selling                       No. of sales calls 350,400    21,900               22,100

Overhead Rates:

Irrigation                 $1,998,432/12,960    = $154.20 per DLH

Machining                 1,670,400/33,408,000 = $0.05 per machine hour

Customer orders      30,636/2,553 = $12 per order

Design                       820/8 = $102.50 per design

Selling                         350,400/21,900 = $16 per sales call

Activity Cost                        Overhead          Actual Cost  

Pools Activity-                       Rates                Assigned

Based  

Irrigation installation                $  154.20    $1,995,502.20 ($154.20*12,941)

Machining (all machine use)        $0.05      1,670,450($0.05*33,409,000)

Customer orders                        $12                30,240 ($12*2,520)

Design                                         $102.50              717.50($102.50*7)

Selling                                         $16             353,600($16*22,100)

b) Levels of Activity:

Unit-level activities: At this level, the costs are concerned with direct materials, direct labor, and machine maintenance.

Product-level activities are specific to a product.

Batch‐level activities require a group (batch) of units to be produced or some processes performed together.

Facility-level activities are support activities required for the development and production of goods and services.  They are organization-wide.

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