Xerox PARC by Alan Kay, Douglas Engelbart, and a group of other researchers in 1981.
Adam D'Angelo is the CEO and co-founder of Quora, an online knowledge market. He was also chief technology officer and <span>vice president of engineering for Facebook.</span>
The correct answer is: Scanner
The scanner is a piece of technology which unlike the printer is an input device which basically scans the top-view of any flat surface (usually paper but is definitely not limited to it) introduced in its effective range using light. The data scanned is then transfered to the Central Processing Unit for futher processing. The processed image can then be outputted and seen on the monitor's display. Once available for printing, the Central Processing Unit will just send the processed image into the printer ad voila, your scanned image is now printed in a piece of paper!
Today, scanners come with printers as a bundle. It is a perfect combination since the printer will just print the image anyway.
Answer:
In the View tab, you will find Zoom Option. Set the Zoom level to 100%.
Explanation:
You need to set the Zoom level to 100%, And you can do this, by setting the zoom level to 100%, from the scroll bar. Or you can move to view tab in the main menu, and then in the Ribbon, you need to select the zoom % and set it to 100 percent. You will then be able to see the entire page. And if you want, you can increase the Zoom level to even further, for getting an even more clearer picture.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
