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rosijanka [135]
3 years ago
6

What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.

Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

The value of log  43is 1.633

Step-by-step explanation:

Explanation:

Suppose you know that:

\begin{array}{l}{\log 2 \approx 0.30103} \\{\log 3 \approx 0.47712}\end{array}

Then note that:

43=\frac{129}{3} \approx \frac{128}{3}=\frac{2^{7}}{3}

So

\log 43 \approx \log \left(\frac{2^{7}}{3}\right)=7 \log 2-\log 3 \approx 7 \cdot 0.30103-0.47712=1.63009

We know that the error is approximately:

\log \left(\frac{129}{128}\right)=\log 1.0078125=\frac{\ln 1.0078125}{\ln 10} \approx 0.00782 .3=0.0034

So we can confidently give the approximation:

\log 43 \approx 1.633

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Answer:

t=\frac{6.6-7.1}{\frac{1.0}{\sqrt{26}}}=-2.550    

Step-by-step explanation:

Data given and notation  

\bar X=6.6 represent the sample mean

s=1.0 represent the sample standard deviation

n=26 sample size  

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\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 7.1 ppm, the system of hypothesis would be:  

Null hypothesis:\mu = 7.1  

Alternative hypothesis:\mu \neq 7.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{6.6-7.1}{\frac{1.0}{\sqrt{26}}}=-2.550    

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Answer:

(11 ft)³

Step-by-step explanation:

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In exponential form, do not solve for the volume. Leave the expression as

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