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Stolb23 [73]
3 years ago
14

Find the area of a regular hexagon with apothem 3 square root 3 mm. Round to the nearest whole number.

Mathematics
2 answers:
NARA [144]3 years ago
8 0
Side = apothem*2/ sqr rt 3
Side = 6 
Perimeter = 6 * 6
Area = (1/2)(perimeter)(apothem)
Area= (1/2)(36)(3\/3)
Area = 93.53
ruslelena [56]3 years ago
3 0

Answer:

Step-by-step explanation:

Given is a regular hexagon with apothem 3 square root 3 mm.

We have hexagon regular can be divided into 6 equilateral triangles with common vertex at the centre of the hexagon

Each equilateral triangle will have 3\sqrt{3} as apothem

Hence using equilateral triangle property

we have side = a (say)

Then \sqrt{3} \frac{a}{2} =3\sqrt{3} \\Or a = 6

Area of each triangle = 1/2 bh = 9 sqrt 3

Hence area of hexagon = 6(9\sqrt{3})=54\sqrt{3}

Use sqroot 3 = 1.732

we get

93.53 square mm.

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Answer:

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Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

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Thus, we have:

(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15

THis is the expression for area.

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