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Stolb23 [73]
3 years ago
14

Find the area of a regular hexagon with apothem 3 square root 3 mm. Round to the nearest whole number.

Mathematics
2 answers:
NARA [144]3 years ago
8 0
Side = apothem*2/ sqr rt 3
Side = 6 
Perimeter = 6 * 6
Area = (1/2)(perimeter)(apothem)
Area= (1/2)(36)(3\/3)
Area = 93.53
ruslelena [56]3 years ago
3 0

Answer:

Step-by-step explanation:

Given is a regular hexagon with apothem 3 square root 3 mm.

We have hexagon regular can be divided into 6 equilateral triangles with common vertex at the centre of the hexagon

Each equilateral triangle will have 3\sqrt{3} as apothem

Hence using equilateral triangle property

we have side = a (say)

Then \sqrt{3} \frac{a}{2} =3\sqrt{3} \\Or a = 6

Area of each triangle = 1/2 bh = 9 sqrt 3

Hence area of hexagon = 6(9\sqrt{3})=54\sqrt{3}

Use sqroot 3 = 1.732

we get

93.53 square mm.

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Answer:

Step-by-step explanation:

cross multiply to get 300=4n then divide by 4 to get 75

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3 years ago
Rectangles JKLM and STUV are similar. The width of JKLM Is 30 feet and the perimeter is 140 feet. The length of STUV is 8 yards.
algol13
Rectangle JKLM:
p = 140 ft
w = 30ft
l = (140 - 2(30))/2 = 40ft
A = (30)(40) = 1200 ft²

Rectangle STUV:
l = 8yd = (8)(3) = 24 ft

24ft/40ft = 3/5

so . .

w = 3/5*30 = 18ft
A = 3/5*1200 = 720 ft²

Ratio of area JKLM:STUV = 1200/720 = 5/3
5 0
3 years ago
Impossible Math Question [ IF YOU GET THIS RIGHT YOU ARE A GENIUS }
devlian [24]
You can just look at it and already tell it’s B
5 0
3 years ago
The on-line access computer service industry is growing at an extraordinary rate. Current estimates suggest that only 20% of the
vitfil [10]

Answer:

The probability is 0.4207

Step-by-step explanation:

The probability of a home-based computer having access to on-line services is p = 0.2 (data from the exercise)

Then, the probability of a home-based computer not having access to on-line services is p = 1 - 0.2 = 0.8

We are going to use this probability (p = 0.8) to solve the exercise.

Let's define the random variable X

X : ''Number of home-based computers not having access to on-line services''

X can be modeled as a binomial random variable

X ~ Bi(p,n)

X ~Bi(0.8,25)

Where p is the success probability and n is the number of Bernoulli independent experiments we are taking place.

We are going to count ''a success'' as a computer not having access to on-line services.

The binomial probability function is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as

nCx=\frac{n!}{x!(n-x)!}

p is the success probability and n the number of Bernoulli independent experiments taking place.

In our exercise,

p=0.8\\n=25

We are looking for :

P(X>20)=P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)

P(X>20)=(25C21)0.8^{21}0.2^{4}+(25C22)0.8^{22}0.2^{3}+(25C23)0.8^{23}0.2^{2}+(25C24)0.8^{24}0.2^{1}+(25C25)0.8^{25}0.2^{0}

P(X>20)=0.1867+0.1358+0.0708+0.0236+0.8^{25}

P(X>20)=0.4207

Finally, the probability of finding that more than 20 of 25 home-based computers do not have access to on-line services is 0.4207

6 0
3 years ago
Write the slope- intercept form of the equation of the line through (0,3) and (1,1)
PolarNik [594]

Answer:

y = - 2x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

Calculate m using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1,1)

m = \frac{1-3}{1-0} = - 2

note the line passes through (0, 3) ⇒ c = 3

y = - 2x + 3 ← equation in slope-intercept form


6 0
3 years ago
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