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3 years ago

Which of the following statements best describes the location of −(−2) on a number line?

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

7 0

Answer:

A. It is 2 units to the right of 0.

Step by step explanation

The given number is - (-2)

When we multiply negative by negative, we get positive.

-(-) = +

Therefore, -(-2) = 2 [By applying the sign rule of multiplication]

2 is nothing but 2 units to the right from 0.

Hence the answer is A. It is 2 units to the right of 0.

Hope you will understand the concept.

Thank you. :)

NeTakaya3 years ago

3 0

The answer is A because the negative on the outside if the parentheses cancels out the negative on the inside of the parentheses making it a positive and there is no other point given so it would be 2 units to the right if 0

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3 years ago

2x - 1 = 7 solved using algebra steps

prisoha [69]

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3 years ago

Enter in standard form the equation of the line passing through the given point and having the given slope.. . B(2, - 5), m = -2

dalvyx [7]

Y = mx + b
slope(m) = -2/3
(2,-5)...x = 2 and y = -5
now we sub, we r looking for b, the y int
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3 years ago

What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8?

Finger [1]

Y=mx+b
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Rearranging gives you the answer of
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7 0

3 years ago

Read 2 more answers

An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.

Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0. $\overline 1$ yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0. $\overline 1$ yd. = (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel pad, m₁ = ρ × V₁

∴ The mass of the steel pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0

3 years ago