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Burka [1]
3 years ago
15

Find the unit rate. Round to the nearest hundredth, if necessary.

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

$12.86 per 1ft2

Step-by-step explanation:

divide when determining the unit rate

180/14=12.8571428571 or (rounded to the nearest hundredths) 12.86

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Jane has a pre-paid cell phone with Splint. She can't remember the exact costs, but her plan has a monthly fee and a charge for
yan [13]

Answer:

The costs of the plan are $0.15 per minute and a monthly fee of $39

Step-by-step explanation:

Let

x ----> the number of minutes used

y ----> is the total cost

step 1

Find the slope of the linear equation

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the ordered pairs

(100,54) and (660, 138)

substitute

m=\frac{138-54}{660-100}

m=\frac{84}{560}=\$0.15\ per\ minute

step 2

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=0.15\\point\ (100,54)

substitute

y-54=0.15(x-100)

step 3

Convert to slope intercept form

Isolate the variable y

y-54=0.15x-15\\y=0.15x-15+54\\y=0.15x+39

therefore

The costs of the plan are $0.15 per minute and a monthly fee of $39

6 0
3 years ago
50 POINTS please only a correct answer
labwork [276]

................................

7 0
4 years ago
Read 2 more answers
Can you figure this out? And then show your work plz?
Salsk061 [2.6K]

Step-by-step explanation:

You can use PEMDAS to solve this problem from left to right.

First, do 15 ÷ 3 to get 5.

Next, do 2 x 10 to get 20.

Lastly, add 5 and 20 to get 25.

<u>15 ÷ 3</u> + 2 x 10

5 + <u>2 x 10</u>

<u>5 + 20</u>

25

3 0
3 years ago
Read 2 more answers
9. Stan’s Deli is situated inside a large industrial park. The weekday gross sales at Stan’s average $1,240, with a standard dev
mr Goodwill [35]

Answer:

0.9792

Step-by-step explanation:

Data provided in the question:

Average gross sales = $1,240

Standard deviation = $180

sample size = 40

Now,

standard deviation of sample average

= \frac{\textup{Standard deviation}}{\sqrt{n}}

= \frac{180}{\sqrt{40}}

= 28.46

Now,

z value for 1200 = \frac{(1200-1240)}{28.46} = -1.4,

and,

p value for (z = -1.4) = 0.0808

therefore,

P(average < $1200) = 0.0808

Thus,

probability that the average over the next 40 weekdays will exceed $1,200

= 1 - 0.808

= 0.9792

7 0
3 years ago
what is this movie movie about a woman who gets robbed by men. calls the police but for some reason the police cant show up so t
swat32

its breaking in or crash


3 0
3 years ago
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