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ANEK [815]
4 years ago
14

You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate. You want to glaze 5 bowls

, and then use the rest for plates. How many plates can you glaze? How much glaze will be left over?
Mathematics
1 answer:
Montano1993 [528]4 years ago
7 0
The answer is 2 plates and .50 glaze left over.

How did I get this?

First lets calculate how many bowls can we glaze. 
5 bowls * 7/8 of a pint = 4.375 pints
4.375 = how many glaze we will need to make 5 bowls.

6 pints - 4.375pints = 1.625 pints left over after we glaze the bowls. 

Now, we need to figure out how many plates we can make with 1.625 glaze.

P X 9/16 = 1.625
Multiply both sides by 16/9 to isolate the variable.
P = 1.625*16/9 
P = 2.88 plates

So, we can only glaze 2 plates. 

How many glaze is left over?
First, how many glaze did we have left over from the bowls? 1.625 glaze
Then, how many plates did we make? 2 at .5625 each = 1.125 glaze

1.625 - 1.125 = .50 glaze left over.

The answer is 2 plates and .50 glaze left over.
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A retail store during the holiday season sold (18) $400 computers, (11) $500 computers, (7) $600
dezoksy [38]

Answer:

$450

Step-by-step explanation:

A way to find the median of a set of numbers is by listing each number one by one and then slowly crossing out the smallest and biggest number one by one. If you end up with two numbers left, then you take the mean of those numbers. To do that, you add the two numbers and divide it by two.

7 0
3 years ago
A vat contains 18 gallons of liquid when a drain pipe opens and the liquid begins to leave the vat at a rate of 4 gallons per ho
SashulF [63]

Answer:

y=-4x+18

Step-by-step explanation:

Let x be the number of hours.

We have been given that a vat contains 18 gallons of liquid when a drain pipe opens and the liquid begins to leave the vat at a rate of 4 gallons per hour.

To graph the amount of liquid first of all we will find the equation of line for our given situation.

Since we know that equation of a line in slope-intercept form is: y=mx+b, where, m = slope and b = y-intercept or initial value.

As liquid is leaving the vat at a rate of 4 gallons per hour, this means that amount of liquid in vat in decreasing 4 gallons per hour. As slope is also known as rate of change, so slope of our given line will be -4. A negative slope means that with each increase in x our y will decrease by 4.

As initially there were 18 gallons of liquid in vat, so our y-intercept will be 18.  

Upon substituting our given values in slope-intercept form of equation we will get,

y=-4x+18

Let us find x-intercept by substituting y=0 in our equation.

0=-4x+18

4x=18

\frac{4x}{4}=\frac{18}{4}  

x=4.5

Now we will draw a line connecting our y-intercept and x-intercept from (0,18) to (4.5,0).  

Please find the attachment for the graph of the given line.


8 0
3 years ago
Please help me with this ratio. ​
Charra [1.4K]

Answer:

\frac{inches}{minute}

Change the feet to minutes by multiplying by 12, and change the hour to minutes.

Speedy: \frac{240}{60}

Slowpoke: \frac{80}{30}

Cleo: \frac{96}{10}

Speedy is the fastest.

\frac{feet}{hour}

  • Speedy: \frac{20}{1}
  • Slowpoke: \frac{\frac{6.666666667}{.5}}{30}
  • Cleo: \frac{8}{\frac{1}{6}}

Change minutes to feet by dividing and change the minutes to hours by multiplying.

<em>Hope this helps and have a great day!!!</em>

<em>Sofia</em>

8 0
4 years ago
Find slope of the line passes through (7, 3)and (9, 6​
RUDIKE [14]

Answer:

slope = 3/2

Step-by-step explanation:

(y2-y1)/(x2-x1)

= (6-3)/(9-7)

= 3/2

Hope this helps!       :3

plz mark as brainliest!

6 0
3 years ago
A decreased by 20% and then increased by 20% express using algebra<br> asapppppp
Ket [755]

Answer:

96%

Step-by-step explanation:

assume the whole number is x

the first thing is decreasing by 20 %

x - 20%x = 80% x

then now the 80%x is the whole number  

now It's the turn of increasing

80%x + 20% * (80% x) = 80%x + 16%x = 96% x

I hope this is hlepful to you !!!!

Feel free to ask me in the comments

6 0
3 years ago
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