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<span>I got 2^(3/5) as the answer</span>
4x^2+23x+15=0
Δ=23^2-4*4*15=529-240=289
x1= (-23+17)/8=-6/8= -3/4
x2= (-23-17)/8=-5
4x^2+23x+15= 4(x+3/4)(x+5)=(4x+3)(x+5)
Answer:
Step-by-step explanation:
Solution by completing the square for:
x2−12x+9=0
Keep x terms on the left and move
the constant to the right side
by subtracting it on both sides
x2−12x=−9
Take half of the x term and square it
[−12⋅1/2]^2=36
then add the result to both sides
x^2−12x+36=−9+36
Rewrite the perfect square on the left
(x−6)^2=−9+36
and combine terms on the right
(x−6)^2=27
Take the square root of both sides
x−6=±27−−√
Simplify the Radical term (1):
x−6=±3–√3
Isolate the x on the left side and
solve for x (1)
x=6±3–√3
therefore (2)
x=6+3–√3
x=6−3–√3
which becomes
x=11.1962
x=0.803848
