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Ludmilka [50]
3 years ago
9

What is the area of the sector bound by the center of the circle and arc CD in the circle below? (1 point) Circle A is shown wit

h a radius labeled 8 feet and a central angle marked 35 degrees. 9.42 ft2 19.54 ft2 34.89 ft2 88.31 ft2
Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

19.54 square feet.

Step-by-step explanation:

The Area of sector of any circle can be calculated by the formula :

Area=\frac{pir^2.\alpha }÷360

Where alpha is the angle made at center of the circle.

In the given question r=8 ft and angle made at center alpha = 35 degrees.

Substituting these values in the formula Area= \frac{\pi(8)^2(35) }{360} =19.54ft^{2}

(Substituting π=3.14)

Answer:19.54 square feet.

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Step-by-step explanation:

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What is the volume of the rectangular prism if the length is 3/4 the width is 2/3 and the hight is 1/2
Leno4ka [110]
Multiply it all together 3/4 is 0.75 2/3 is 0.66 1/2 is 0.5 now do in your calculator 0.75+0.66+0.5 and becase everything is in fractions remember that you have to convert your decimal into a fraction your answer is 1 91/100
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3 years ago
10x + (-8)= -3x + 2<br> How do I solve this in pemda order
larisa [96]

Answer:

x= 10/13

Step-by-step explanation:

First, we need to put the variable on one side and the constants on another side.

Also a positive and a negative equal a negative. [this is related to +(-8)]

10x+(-8)= -3x+2

+3x         +3x

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4 0
3 years ago
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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antiseptic1488 [7]

Answer:

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The period is the change in x required to make a change of 2π in the argument to the sine function:

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The frequency is the reciprocal of the period, so is 1/π. There are no matching answer choices.

7 0
2 years ago
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