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2 years ago

How much might a home buyer expect to pay in closing costs on a $220,000

2 answers:

8 0

$220 000 is the total cost of the house that a buyer bought.
Prior to that, he paid 10% of the amount for down payment.
Now, we need to find the amount he will need to pay to paid off the house he bought.
=> 10% = 10 / 100
=> 0.1
We already have the value of 10%, now multiply this to the total amount of the house
=> 220 000 x 0.1
=> 22 000 – he paid this amount for down payment.
Now, let’s subtract his down payment from the total amount.
=> $220 000 – 22 000
=> $198 000
Thus, the home buyer will pay 198 000 to paid off the house he bought.

serg [7]2 years ago

6 0

Answer:

220000*.1=22000

Step-by-step explanation:

You might be interested in

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

2 years ago

Scientists have increased their ability to make observations beyond their own senses through the invention of specialized equipm

just olya [345]

Answer:

Step-by-step explanation:

A is rather a strange choice. The tools are used as extensions of our senses. That's all that technology has done. We still need to observe things for ourselves if we are to learn. I actually really do not know what this statement means. My answer reflects what I think is true. Our need to observe and think is not hindered.

B is never going to be true. We still have to test things out, even with the best tools that we have.

C: The exact opposite is true. Our knowledge of the universe has expanded beyond our belief with the better tools of technology that we have.

D: This is the opposite of C and is the answer.

5 0

2 years ago

Casandra needs 2 meters of string for her kite how many centimeters of string does she need

inna [77]

Answer:

200 cm

Step-by-step explanation:

2*100= 200

4 0

2 years ago

Read 2 more answers

1. John’s age is three times that of his sister. When you add John’s age to his sister's age, you get 36. How old are John and h

iren [92.7K]

Answer:

sister = 6 years

John=18 years

Step-by-step explanation:

A(S) + 12 = 3 * A(S), subtracting A(S) from both sides one gets 12 = 2 * A(S). Now dividing both sides by 2 we get A(S) = 12/2 = 6 . Therefore, the age of the sister is 6 years when her brother John is three times as old, that is 18 years.

6 0

2 years ago

Read 2 more answers

Simplify using the distributive property. 5 Marks 1/5(4m+20) 9(5/9 y-1/3)

Zarrin [17]

Answer+Step-by-step explanation:

$\frac{1}{5} \left( 4m+20\right) =\frac{4}{5}m + \frac{20}{5} = \frac{4}{5}m + 4$

$9\left( \frac{5}{4} y-\frac{1}{3} \right) =\frac{9\times5}{9} y-\frac{9}{3} = 5y - 3$

4 0

1 year ago