X is Kevin; Y is Dan
X = 3Y
X - 4 = 5(Y - 4)
3Y - 4 = 5(Y - 4)
3Y - 4 = 5Y - 20
+ 4 +4
4 cancels each other out.
3Y = 5Y - 16
- 5 -5
5 cancels each other out.
-2Y = -16
/2 /2
Y = 8
X = 3Y;
X = 3 x 8;
Thus,
X = 24;
Kevin(x) is 24
Δ = (8i)^2 - 4*(-25) => Δ = -36 +100 => Δ = 64 => x1 =(-8i + 8)/2 => x1 = -4i +4;
x2 = (-8i - 8)/2 => x2 = -4i-4; in this case, your solutions are complex conjugates.
Answer:
Gcvmjedbgkje2m
Step-by-step explanation:
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Answer:
−t+24
Step-by-step explanation:
Answer:
4
Step-by-step explanation: