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mel-nik [20]
3 years ago
14

SOLVE. x cubed over x squared - 4 divided by x cubed - 9x squared over x squared + 7x -18

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0
<span>x^3/x^2-4/x^3-9x^2/x^2+7x-18
</span><span>factor everything so you know what to cancel out; Also, take the bottom "fraction"; turn it over, spank it, and multiply it to the top "fraction"; like this:
      xxx                          (x+9)(x-2)
           --------- * ----------
          (x-2)(x+2) xx (x-9)
</span>
<span>Now cancel like terms top to bottom
    x(x+9)
    ----------
  (x+2) (x-9)</span>
Tom [10]3 years ago
3 0
\frac{ x^{3} }{ x^{2} -4}: \frac{ x^{3} -9 x^{2} }{ x^{2} +7x-18}= \\ = \frac{ x^{3} }{(x+2)(x-2)}* \frac{ x^{2} +7x-18}{ x^{2} (x-9)}= \\ = \frac{ x^{3} }{(x+2)(x-2)}* \frac{(x-2)(x+9)}{ x^{2} (x-9)}= \\ = \frac{x(x+9)}{(x+2)(x-9)}
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sleet_krkn [62]

Answer:

<h2><em><u>The answer is: 18</u></em></h2>

<em><u>Hope this helps you! </u></em><em><u>.</u></em>

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Salsk061 [2.6K]

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

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\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

Therefore, the values of x and y are 5 and 2 respectively.

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Answer:

(4,10) I think !

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