Answer:
Pvalue = 0.063008
Step-by-step explanation:
Given :
Sample size, n = 63
The test statistic = - 1.53
To test if average room price is significantly different from $110 ; μ = $110
H0 : μ = 110
H1 : μ < 110
From the test statistic value obtained, we could see that the test is left tailed
The Pvalue :
P(Z < - 1.53) = 0.063008
If the claim is to be tested at 5% level of confidence then
Pvalue > 0.05 ; Hence, we fail to reject the. NULL. Hence, average price is not significantly different from $110
Just use the distance formula.. (-3 - -4)squared + (-5 - 6)squared
Answer:
x = 56.31%
Step-by-step explanation:
to find x, use ![tan^{-1}](https://tex.z-dn.net/?f=tan%5E%7B-1%7D)
x = ![\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=%5Cfrac%7Bopposite%7D%7Badjacent%7D)
x = ![\frac{15}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B10%7D)
x = 1.5
x = 56.3099
56.3099 = 56.31