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zvonat [6]
4 years ago
14

How many solutions does the following system have -5x-y=5 x-2y=-1

Mathematics
1 answer:
Colt1911 [192]4 years ago
5 0
!! Answer will be D !!
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Liliana wants to start a seventh-grade computer club at Hamden Middle School. She surveyed 20 seventh-grade students at the town
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18/20 or 9/10 would be the answer. Hope this helps!
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3 years ago
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Copy down the calculation below and insert one pair of brackets so that the
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Answer:

12+24÷(2^2+8)

Step-by-step explanation:

that should be the answer

if you struggle with questions that are like this use trial and error

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30 POINTS! Quilt squares are cut on the diagonal to form triangular quilt pieces. The hypotenuse of the resulting triangles is 3
Vesna [10]
C^2= a^2 + b^2                  a=b
34^2= a^2 + a^2
1156=2a^2
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The side length is 24.04
            Or I got this also
Using the special triangle theorem , an isosceles triangle has a diagonal equal to the square root of 2 of the legs of the triangle. In this case, the length of the legs is 34/ sqrt of 2 or equal to 24.04 units . This rule is based on the Pythagorean theorem
If the length of each side = x.

By Pythagoras' Theorem:

x² + x² = 34²

2x² = 34²

x² = 34² / 2

x² = 578

x = √578

<span>x ≈ 24.04 inches
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3 0
3 years ago
An ellipse has a co-vertex at (–8, 9) and a foci at (4, 4). If the center of the ellipse is located below the given co-vertex, t
vovikov84 [41]

Answer:

Step-by-step explanation:

“the center of the ellipse is located below the given co-vertex”

Co-vertex and center are vertically aligned, so the ellipse is horizontal.

Equation for horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

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center (h,k)

vertices (h±a, k)

co-vertices (h, k±b)

foci (h±c,k), c² = a² -b²

One co-vertex is (-8,9), so h = -8.

One focus is (4,4), so k = 4.

Center (h,k) = (-8,4)

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b = |9-k| = 5

a² = c² + b² = 169

(x+8)²/169 + (y-4)²/25 = 1

7 0
3 years ago
8 necklace have 864 beads in all how many beads will 15 such necklace have?​
Elza [17]
864/8 gives you 108. There are 108 beads on each necklace. So for 15 necklaces, multiply 108 and 15. There are 1,620 beads in 15 necklaces.
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