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vaieri [72.5K]
3 years ago
12

1/7 divided by 4 equals

Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0
1/ 28 is the answer.
= 1/7 ÷4
= 1/7 ÷ 4/1
=1/7 X 1/4 
Multiply top by top, bottom by bottom
=1/28 

If you do not know how to do it:
First make both sides into a fraction ( Whole numbers always have a 1 as a denominator).
Then you reciprocate (Flip) the second fraction.
Finally you multiply top by top, bottom by bottom
You get the answer!<span />
You might be interested in
The equation of the line that contains the points (-8, 1) and (0, -5) is
posledela

Answer:

y = -3/4x -5 (G)

Step-by-step explanation:

Find the slope by using the slope formula. (It's hard to format here so look it up)

Basically, it is y2 - y1/x2 - x1

-5 - 1/ 0 + 8

-6/8 = -3/4

The slope is -3/4.

Plug in for y = mx + b

y (y coordinate) = -5

x (x coordinate) = 0

slope (m) = -3/4

-5 = -3/4(0) + b

-5 = 0 + b

b = -5

y = -3/4x -5

5 0
2 years ago
Translate<br> Solve the equation.<br> 3m= 5(m + 3)-3<br> HELP
kvasek [131]

Answer:

m = -6

Step-by-step explanation:

3m= 5(m + 3)-3

Distribute

3m = 5m +15 -3

Combine like terms

3m = 5m +12

Subtract 5m

3m-5m = 5m+12-5m

-2m = 12

Divide by -2

-2m/-2 = 12/-2

m = -6

7 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0
aleksandr82 [10.1K]
<span>the correct equation is
- 4j² + 3j - 28 =0

 ax² + bx + c,
 a = -4, b=3  c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439 
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
 The answer there is no real roots</span>
8 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
2 years ago
Help please! 50 Points! PLEASE DONT RESPOND IF YOU DO NOT KNOW.
Sphinxa [80]

Answer:

e.869.58units^2

f. 96m^2

g. 184m^2

Step-by-step explanation:

e.

484 square

176 triangle

209.58 equilateral triangle

f. 196 total are - mini square 25+25+25+25= 96m^2

g. 22+66+80+16=184m^2

3 0
3 years ago
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