Question

50 points, question down below. :)

Answer 1

ツHelloツ

The answer:M=3

#HarLeyQuinn

Answer 2

$The\ domain:\\m+3\neq0\ \wedge\ 3-m\neq0\\m\neq-3\ \wedge\ m\neq3\\\\\dfrac{3}{m+3}-\dfrac{m}{3-m}=\dfrac{m^2+9}{m^2-9}\\\\\dfrac{3}{m+3}-\dfrac{m}{-(m-3)}=\dfrac{m^2+9}{m^2-9}\\\\\dfrac{3}{m+3}+\dfrac{m}{m-3}=\dfrac{m^2+9}{m^2-9}\\\\\dfrac{3(m-3)}{(m+3)(m-3)}+\dfrac{m(m+3)}{(m+3)(m-3)}=\dfrac{m^2+9}{m^2-9}\\\\\dfrac{3m-9+m^2+3m}{m^2-9}=\dfrac{m^2+9}{m^2-9}\iff m^2+6m-9=m^2+9\ \ \ \ |-m^2\\\\6m-9=9\ \ \ \ |+9\\\\6m=18\ \ \ \ |:6\\\\\boxed{m=3\notin D}$

Answer: No solution