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skelet666 [1.2K]
4 years ago
12

The sum of the root of 3x^2+11x-4=0

Mathematics
2 answers:
klemol [59]4 years ago
6 0

Answer:

Option (a) is correct.

The sum of roots of given quadratic equation -\frac{11}{3}

Step-by-step explanation:

Given quadratic equation 3x^2+11x+4=0

We have to find the sum of roots.

Consider the given quadratic equation 3x^2+11x+4=0

For a given standard quadratic equation ax^2+bx+c=0 , we have

Sum of roots is given by -\frac{b}{a}

and product of roots is given by \frac{c}{a}

Thus, for the  given quadratic equation 3x^2+11x+4=0

a = 3 , b = 11 , c = 4

So, the sum of roots is given by -\frac{b}{a}

Substitute, we get,

Thus, The sum of roots of given quadratic equation -\frac{11}{3}

dybincka [34]4 years ago
5 0
A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately. In other words, we are going to solve as many equations as there are terms in the product. <span>Any solution of term = 0 solves product = 0 as well.
</span>
Solve  :    3x-1 = 0<span> 
 </span><span>Add </span> 1  to both sides of the equation :<span> 
 </span>                     3x = 1 
Divide both sides of the equation by 3:
                     x = 1/3 = 0.333<span> 
</span>
 Solve  :    x+4 = 0  Subtract  4  from both sides of the equation :                       x = -4 

<span>x = -4<span> and x = 1/3 or 0.333</span></span>
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