Question

3. Every time Deucalion threw one stone over his shoulder, eight people sprang

Answer 1

Answer:

1156

Step-by-step explanation:

When Deucalion threw one stone over his shoulder, 8 people appear. So, for every stone, we have 8 new people.

Therefore, if Deucalion threw 68 stones, the number of people that would appear is

$n_1=68\cdot 8 =544$

Instead, when Phyrra threw a stone, 9 people appear. So, for every stone, we have 9 new people.

Therefore, if Phyrra threw 68 stones, the number of people that would appear is

$n_2=68\cdot 9 =612$

And so, we can now calculate the total number of people that appear after each had thrown 68 stones:

$n=n_1+n_2=544+612=1156$