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sesenic [268]
3 years ago
11

Sneha is inspecting the average cleanliness of the rooms in a hotel. There are 10 floors in the hotel, each with 20 rooms. From

each floor, she randomly selects 2 rooms and inspects them and then takes the average of these scores. What type of sampling did Sneha use
Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer: Stratified sampling

Step-by-step explanation:

Stratified sampling is a particular kind of random sampling technique.

Here , the researcher splits the entire population into distinct groups known as strata.

Then he draw a sample by taking participants from each strata and continue his work on sample.

As per given ,

Researcher = Sneha

Strata = Each floor

Since from each floor she randomly selects 2 rooms and inspects them and then takes the average of these scores.

Therefore , Sneha used the Stratified sampling technique.

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2x + 3x + 4 equals .
RUDIKE [14]
Add like terms
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2x+3x=5x

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answer is 5x+4
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3 years ago
You work for a horse farrier. You take a random sample of 75 Quarter Horses and determine that their mean height is 15.2 hands.
Evgesh-ka [11]

Answer:

B) You conclude that the mean height of all Quarter Horses is close to 15.2 hands

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the probability of picking 4 consonant and 1 vowels when 5 letters are picked (without replacement) from a set of alphabet
Ganezh [65]

The required probability is 0.45

We have total 26 letters in english, of which 21 are consonants and 5 are vowels.

According to the question, we have to select 5 of them of which 4 will be consonants and 1 will be vowel.

Suppose we want to have the vowel in the first selection, so the probability of picking a vowel is equal to the quotient between the number of vowels and the number of total number of letters.

So the probability is 5/26

Now, a letter has been selected, so in the set, we have 25 letters left.

In the next 4 selections, we must select consonants.

In the second selection the probability is 21/25

In the third selection the probability is 20/24

In the fourth selection the probability is 19/23

In the last selection the probability is 18/22

So, the probability is (5/26)×(21/25)×(20/24)×(19/23)×(18/22)

Now, remember that we take that the vowel must be in the first place, but it can be in any five places, so if we add the permutations of the vowel letter we have,

P = 5×(5/26)×(21/25)×(20/24)×(19/23)×(18/22) = 0.45

Learn more about probability here :

brainly.com/question/251701

#SPJ10

5 0
1 year ago
By the way, in the picture it's both to a power of 3 if you can't see. Thank you.
disa [49]
PERIODDDDDDDSDDDDDDDDDDDDDD
5 0
2 years ago
The picture frames shown are both squares. The area of the smaller frame is 1/4 the area of the larger frame. Find the side leng
baherus [9]
Area of smaller frame =1/4×36=9sq.in
side of smaller frame =
\sqrt{9  }  = 3in
side of larger frame
=  \sqrt{36}  = 6in
4 0
3 years ago
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