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Mrac [35]
3 years ago
10

What is the value of f(–1) when f(x) = 2x + 2? f(–1) =

Mathematics
2 answers:
sweet [91]3 years ago
8 0

Answer: f(-1)= 0

Step-by-step explanation:

f(-1)

x=(-1)

f(-1) = 2x + 2

f(-1) = 2(-1) + 2

2 x (-1) = -2

-2 +2 = 0

EleoNora [17]3 years ago
4 0

Answer:

-3/2 = f

Step-by-step explanation:

f(-1) =2x+2

-1f=2x+2

-1f-2=2x

-3=2x

-3/2=x

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6 0
4 years ago
A recipe for pie dough calls for a ratio of butter to flour of 3/4:2 1/2. If you plan to use 10 cups of flour, how much butter s
dybincka [34]

Answer:

Therefore 3 cup of butter should be used to keep the same ratio.

Step-by-step explanation:

Given, a recipe for pie dough calls for ratio of butter to flour of \frac{3}{4}:2\frac{1}{2} =\frac{3}{4} :\frac{5}{2}

{butter}:{flour} =\frac{3}{4} :\frac{5}{2}

\Rightarrow\frac {butter}{flour} =\frac{\frac{3}{4} }{\frac{5}{2}}

Let, x cups of butter needed.

Given,Flour = 10 cups

\therefore \frac {x}{10} =\frac{\frac{3}{4} }{\frac{5}{2}}

\Rightarrow {x} =\frac{\frac{3}{4}\times 10 }{\frac{5}{2}}

\Rightarrow {x} =\frac{{3}\times 10\times 2 }{5\times 4}}

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3 0
3 years ago
How do I integrate trig functions
katrin [286]
Integrate sin(3x+1) with respect to x.  Use the substitution method.  Let u=3x+1 be y our substitution.  Then du/dx = 3, and du = 3dx.

Then we have "integrate sin u with respect to u" .  Here's where things are just a bit tricky at first.  You have "integrate sin (3x+1) with respect to x."  If u = 3x+1, then du/dx = 3 and du=3dx.   But we don't have 3dx; we have only dx.  Manipulate du=3dx as follows:  du/3 = dx.

Then, "integral of sin (3x+1) dx"  => "integral of sin u (du/3)"

and this is equivalent to   (1/3) "integral of sin u du."  We get:
(1/3)(-cos u) + c, or (-1/3)*cos u + c.  Finally, subst. 3x+1 for du, obtaining

(-1/3)*cos(3x+1) + C (answer).

You should find the derivative of this as a check.  If the result of your differentiation is sin(3x+1), your integral was correct.  Otherwise, it's not.

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