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Ket [755]
3 years ago
10

I need help with number 9!

Mathematics
1 answer:
Alisiya [41]3 years ago
8 0

9. √105 is irrational (105 is not the square of an integer) Its value is near +10.

-4 is an integer (and rational)

4/3 is a rational number

Smallest to largest, these are -4, 4/3, √105.

10. The nearest square less than 14 is 9 = 3×3. The nearest square greater than 14 is 16 = 4×4. 14 is closer to 16 than to 9, so we expect 4 to be the integer closest to its square root. (√14 ≈ 3.74, closer to 4 than to 3.)

11. The numbers are in the same order; only the location of parentheses has changed. The property that lets you do that with addition is the associative property.

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Evaluate |x + y|, for x = 8 and y = -15.
Mademuasel [1]
First, we substitute the numbers to the corresponding variables.

|(8) + (-15)|

And we change the plus sign since we’re just basically subtracting.

|8 - 15|

|-7|

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3 years ago
A football team loses 5 yards on each of 3 consecutive plays. What signed number represents the team's total loss of yards on th
mario62 [17]

Answer:

change below :)

Step-by-step explanation:

You would start out at in the middle of a number line (horizontal). After the first play, you would move to the left on the line 5 spots (to simulate 5 yards lost) and then make a dot to show your new position. You would do the same thing for the next two plays, moving 5 spots to the left each play and creating a new starting point each time. The total spots moved after the 3 plays is 15 spots to the left.

3 0
2 years ago
What is the median to <br> -4 -6 0 -1 -1 -0
elena-14-01-66 [18.8K]

Answer:

-0.5 is the answer

Step-by-step explanation:

ARRANGING THE VALUE IN ASCENDING ORDER

-6,-4,-0,-1,-1,0

N=6(counting the above numbers of ascending order)

Position of median=(N+1/2)th items

=(6+1/2)th items

=(7/2)th items

=(3.5)th items

IF THE ANSWER IS IN POINT YOU SHOULD FIND THE AVERAGE,

3.5th itemsis the average of 3rd and 4th items

Median=-0+(-1)/2

=-0-1/2

=-1/2

=-0.5

Hope it us helpful for you

6 0
3 years ago
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