What are the answers to these three questions? horrible at math. ty.

Mathematics

1 answer:

klemol [59]4 years ago

5 0

3x^2 + 2x - 6 if x = -2

=3(-2)^2 + 2(-2) - 6
=12 - 4 - 6
= 2

5x^2 + 6x - 2 if x = -2

=5(-2)^2 + 6(-2) - 2
=20 - 12 - 2
= 6

-2x^3 + 2x^2 if x = 2

= -2(2)^3 + 2(2)^2
= -16 + 8
= -8

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What is the area of the sector a.) 10π cm^2b.) 16π cm^2c.) 40π cm^2d.) 64π cm^2

Natalija [7]

Answer:

C. 40π cm²

Explanation:

• The central angle of the sector = 225 degrees

• The radius of the sector = 8cm

For a sector of radius r and central angle θ, we calculate the area using the formula below:

$\text{Area}=\frac{\theta}{360\degree}\times\pi r^2$

Substituting the given values, we have:

$\begin{gathered} \text{Area}=\frac{225}{360}\times\pi\times8^2 \\ =\frac{5}{8}\times64\times\pi \\ =5\times8\times\pi \\ =40\pi cm^2 \end{gathered}$

The area of the sector is 40π cm².

3 0

1 year ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$