10 kids total
picking Truman would be 1 out of 10 or 1/10
then there would be 9 kids left so picking Ryan would be 1 out of 9 or 1/9
the probability of picking both would be 1/10 * 1/9 = 1/90
Answer:
See Below
Step-by-step explanation:
x(2x) - 4(2x) + x(3) - 4(3)
= 2x² - 8x + 3x -12
= 2x²-5x-12
If the ball was thrown straight up at 24 ft/sec when it was 5 ft above the ground, the ball reached a maximum height of 7.25 m
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<h3>Further explanation</h3>
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
<h2>D = b² - 4 a c</h2>
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots

An axis of symmetry of quadratic equation y = ax² + bx + c is :

Let us now tackle the problem!
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<u>Given:</u>



<u>Asked:</u>

<u>Solution:</u>
<em>At the maximum height , velocity is 0 m/s:</em>












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<h3>Learn more</h3>
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<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
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Keywords: Quadratic , Equation , Discriminant , Real , Number
#LearnWithBrainly
Answer:
(0, -5)
Step-by-step explanation:
3/12 ; 1/6 ; 1/3
Adam must first get the least common multiple of each denominator.
12 : 12, 24, 36
6 : 6, 12, 18
3 : 3, 6, 9, 12
12 is the least common denominator.
We, then, multiply each denominator by a number that will produce 12.
12 x 1 = 12
6 x 2 = 12
3 x 4 = 12
Each number multiplied to the denominator must be the number used to multiply each numerator.
3/12 * 1/1 = 3/12
1/6 * 2/2 = 2/12
1/3 * 4/4 = 4/12
Since they now share a common denominator, the numerator will become the basis of the fraction's value. The greater the numerator, the greater the fraction's value.
Fractions in order from least to greatest = 2/12 ; 3/12 ; 4/12
Substitute each fraction with its original fraction:
2/12 ⇒ 1/6 : least
3/12 ⇒ 3/12 : middle
4/12 ⇒ 1/3 : greatest