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Kay [80]
3 years ago
10

Suppose you use an app that randomly generates a number from 1 to 15.

Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

4 out of 15

Step-by-step explanation:

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The time (in number of days) until maturity of a certain variety of tomato plant is Normally distributed with mean μ. You select
VLD [36.1K]

Answer: 60.93 < μ < 69.07

Step-by-step explanation: The true mean of a set of data is between an interval of values with a percentage of precision, e.g., a <u>99% confidence interval</u> means we are 99% confident the true mean is between the lower and upper limits.

To find the interval, use

x±z\frac{s}{\sqrt{n}}

z is z-score related to the % of confidence level

In this case, a 99% confidence interval is 2.576

x is sample mean

Calculating:

x=\frac{63+69+62+66}{4}

x = 65

65±2.576\frac{3.16}{\sqrt{4}}

65±4.07

Confidence Interval: 60.93 < μ < 69.07

Meaning that we are 99% sure the population means is between 60.93 and 69.07.

7 0
2 years ago
What are the zeros of the quadratic function represented by this graph?​
mario62 [17]

Answer:

Step-by-step explanation:

answer : C  when this graph passes trough x-axis

6 0
3 years ago
the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base​
wel

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

The breadth of cuboid = b cm

The height of cuboid = h cm

<u>According to question</u>

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 =  2 ×(l × b + b × h + h × l)

Or,  (l × b + b × h + h × l) = \dfrac{95}{2}          ....1

<u>Similarly</u>

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = \dfrac{63}{2}              ......2

Putting value of eq 2 into eq 1

so,  (l × b +  \dfrac{63}{2} ) = \dfrac{95}{2}    

Or, l × b = \dfrac{95}{2} - \dfrac{63}{2}    

Or,  l × b = \dfrac{95 - 63}{2}

i.e l × b = \dfrac{32}{2}

so, l × b = 16

<u>Now, Again</u>

∵The Area of the base = ( length × breadth ) cm²

So, z =  l × b

i.e z = 16 cm²

So, The Area of the base = z = 16 cm²

Hence,The Area of the base is 16 cm² . Answer

5 0
3 years ago
How do you write 78,621,087 in expanded notation and expanded form?
Inga [223]
70,000,000+8,000,000+600,000+20,000+1,000+80+7 = 78,621,087
4 0
3 years ago
What is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides?
Viktor [21]
Let’s find the volume of the small cubes.
1/3^3
1/27
Now multiply this by 567
567•(1/27)
21
The volume of the box is 21 inches cubed.
8 0
3 years ago
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