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Aleksandr [31]
3 years ago
10

What is the probability that a randomly selected reference book is hardcover?

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

0.4

Step-by-step explanation:

maxonik [38]3 years ago
5 0

Answer:  The correct option is (B) 0.4.

Step-by-step explanation:  We are given to find the probability that a randomly selected reference book is hardcover.

Let, S denote the sample space for the experiment of selecting a book.

Then, n(S) = 60.

Let A denote the event that the selected book is is a reference one and B denote the event that the selected book is a hardcover.

Then, according to the given information, we have

n(A)=25,~~~n(B)=40,~~~n(A\cap B)=10.

So,

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{25}{60}=\dfrac{5}{12},\\\\\\P(B)=\dfrac{n(B)}{n(S)}=\dfrac{40}{60}=\dfrac{2}{3}\\\\\\P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{10}{60}=\dfrac{1}{6}.

Therefore, the probability that a randomly selected reference book is hardcover is equal to the conditional probability of event B given A.

That is, the required probability is

P(B/A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{\frac{1}{6}}{\frac{5}{12}}=\dfrac{1}{6}\times\dfrac{12}{5}=\dfrac{5}{5}=0.4.

Option (B) is correct.

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Rufina [12.5K]
It is 8 units because if you start at -5,2 you will have to go up 8 units to get to -5,10. They are 8 units away from each other.
5 0
3 years ago
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7x +39 &gt; 53<br> AND<br> 16x + 15 &gt; 31
bezimeni [28]

Answer:

x > 2

Step-by-step explanation:

7x +39 > 53

AND

16x + 15 > 31

7x > 14

AND

16x > 16

x > 2

AND

x > 1

And is intersection, which is x > 2

4 0
3 years ago
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Determine the similarity ratio for each pair of similar solids.
Lostsunrise [7]

Answer:

a) k =  \frac{7}{4}

b) {k}  =   \frac{13}{9}

Step-by-step explanation:

a) The similarity ratio is given by;

{k}^{2}  =  \frac{image \: size}{corresponding \: object \: size}

This implies that:

{k}^{2}  =  \frac{78.4}{25.6}

This simplifies to:

{k}^{2}  =  \frac{49}{16}

Take positive square root:

{k} =  \sqrt{ \frac{49}{16} }

k =  \frac{7}{4}

Therefore the similarity ratio is:

k =  \frac{7}{4}

b) This time the size are in volumes: We still use the same approach. But this time:

{k}^{3}  =  \frac{175.76}{58.32}

{k}^{3}  =  \frac{2197}{729}

Take cube root:

{k}  =   \sqrt[3]{\frac{2197}{729} }

{k}  =   \frac{13}{9}

The similarity ratio is

{k}  =  \frac{13}{9}

5 0
3 years ago
Please can someone help me please
Tomtit [17]
You can use variables to solve this problem. Lets say that m is men, w is women, and c is children. m+w+c=266
four times as many men as children in ‘math words’ would be 4c=m
twice as many women as children would be 2c=w
what we can do now is plug those in to make everything easier with one variable
4c+2c+c=266
7c=266
c=38 now we have how many children, and we need to plug it back into what we have for women and men.
4c=m 4(38)=m m=152
2c=w 2(38)=w w=76


152 men, 76 women, and 38 children
7 0
3 years ago
In circle L with m^KLM 54 and KL= 10 units, find the length of arc KM.
qwelly [4]

Given:

In circle L, measure of angle KLM is 54 degrees and KL = 10 units.

To find:

The length of arc KM.

Solution:

The formula for arc length is:

s=2\pi r\times \dfrac{\theta}{360^\circ}          ...(i)

Where, r is the radius of the circle and \theta is the central angle in degrees.

The measure of KL is 10 units, it means the radius of the circle L is 10 units.

The measure of angle KLM is 54 degrees, it means the measure of central angle on arc KM is 54 degrees.

Putting \pi=3.14, r=10,\theta=54^\circ in (i), we get

s=2(3.14)(10)\times \dfrac{54^\circ}{360^\circ}

s=20(3.14)\times 0.15

s=9.42

Therefore, the length of arc KM is 9.42 units.

3 0
3 years ago
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