Okay so for Mike, he has $22 in his account.
He deposits $11.50 in it each week, and they want to know how much he has in 12 weeks.
First, multiply $11.50 * 12, which is $138. Then add the $22 that's already in the account, which brings him to $160.
Now for Tim,
He has $218 and withdraws $13 every week.
13 * 12 = 156
Now subtract 218 and 156
218 - 156 = 62
So at the end of 12 weeks, Mike has $160 dollars in his account, and Tim has $62 in his account.
Given:
The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute
in (i).


Putting
in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute
in (ii).

Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute
in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get




Putting
in (iv), we get



Putting
in (ii), we get
Therefore, the required quadratic equation is
.
A^2-b^2=(a+b)(a-b)
1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
Question:
Solve each calculation. Be sure to report your answer with the correct number of significant figures.
5.61000 dg × 1.1010 dg
12.0 m ÷ 3.1415 m
Answer:
1.
=
2. 
Step-by-step explanation:
1. 5.61000 dg × 1.1010 dg
We start by representing each digit using scientific notation


Then, Multiply both numbers

First, rearrange


From law of indices,
;
So, we have

Because 5.61000 is given in 3 significant figures and 1.1010 is given in 4 significant figures, we approximate the result to 4 significant figures
This gives
Hence,
=
2.
12.0 m ÷ 3.1415 m
Using proper notation
12.0 m ÷ 3.1415 m = 
We start by representing 3.1415 using scientific notation

By substitution;

Take
to the numerator

From law of indices,
= 10000

Multiply

Divide

Because 12.0 is given in 2 significant figures and 3.1415 is given in 5 significant figures, we approximate the result to 5 significant figures
