how to prove that any segment whose ends lie on the two bases of a trapezoid is bisected by the midsegment of the trapezoid
1 answer:
Looking at the image I have attached (with MN being the midsegment of the trapezoid), For any PQ with P and Q lying on the bases of the trapezoid there exists ON with O being the point of intersection between PQ and MN. ON must be parallel to PC because ON is part of MN and PC is a part of DC, and MN and DC are parallel. And N must be the midpoint of CB because MN is the midsegment of the trapezoid, so MN must bisect CB. And since ON is parallel to PC and bisects CB, that means it is a midsegment of QBCP and must bisect PQ.
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For a sample size of 20 players, 68% of the sample means fall within 19.32 and 20.98
<h3>What is a sample size?</h3>The sample size is a term used in market research for defining the number of subjects included in a sample size. By sample size, we understand a group of subjects that are selected from the general population and is considered a representative of the real population for that specific study.
Empirical rule states that for a normal distribution, 68% of the values are within one standard deviation from the mean, 95% of the values are within two standard deviation from the mean and 99.7% of the values are within three standard deviation from the mean.
For a population mean of 20.15 and a standard deviation of 3.7
68% are within μ ± σ/√n,
hence,
68% = 20.15 ± 3.7/√20 = (19.32, 20.98)
For a sample size of 20 players, 68% of the sample means fall within 19.32 and 20.98.
To learn more about sample size from the given link:
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