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sdas [7]
3 years ago
8

Find the value of z.

Mathematics
1 answer:
Leokris [45]3 years ago
3 0

The exterior angle at the intersection of the tangent and secant has a measure that is half the difference between the intercepted arcs.

... ((10x+20) -80)/2 = 2x+15

... 5x -30 = 2x +15

... 3x = 45

... x = 15

So, the unknown arc to the right has measure

.. 10x + 20 = 10·15 +20 = 170

And the arcs of the circle total 360°.

... 80 + z + 170 = 360

... z = 360 - 250 = 110 . . . subtract 250 from both sides

The appropriate choice for the value of z is

... B. 110

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75

Step-by-step explanation:

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Leviafan [203]

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Step-by-step explanation:

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8 0
3 years ago
In the lottery game known as 6/36, a player picks six numbers from 1 to 36. (a) How many different ways are there for the player
Goryan [66]

Answer:

Step-by-step explanation:

Part A

This is a combination problem. Order does not matter.

36C6

36!/(30! 6!)

36 * 35 * 34 * 33 * 32 * 31/ 6!

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1947792

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3 0
3 years ago
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
SCORPION-xisa [38]

Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

7 0
3 years ago
A farmer decides to enclose a rectangular garden, using the side of a barn as one side of the rectangle. What is the maximum are
kifflom [539]
Garden
max area is if the sides are as equal as possible
so he should try to make a square (ideal is a circle, but barn walls are normally straight)
squaer perimiter=4 times legnth of 1 side
perimiter=amount of fencing=80
80=4s
divide 4
20=s
one sides=20

area=legnth times width
in squaer, legnth=width

20=legnth
20=width
area=20 times 20=400

dimetions are 20ft by 20ft to give 400ft^2
(fun fact, if it were a circle, the area would be about 509.5ft^2)


answer is 20ft by 20ft and area=400ft^2
7 0
3 years ago
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